Math, asked by ayushpanchal606, 8 months ago

5.
In a group of 84 persons, each plays at least one game out of
three viz. tennis, badminton and cricket. 28 of them play cricket,
40 play tennis and 48 play badminton. If 6 play both cricket and
badminton and 4 play tennis and badminton and no one plays all
the three games, find the number of persons who play cricket
but not tennis. What is the importance of sports in daily life?

Answers

Answered by sahanaraghupathy07
2

Answer:

Step-by-step explanation:Let C, T, B denote the set of students who play cricket, tennis and badminton respectively

Then we have, n(U) = n(C ∪ T ∪ B) = 84,

n(C) = 28, n(T) = 40, n(B) = 48,

n(C ∩ B) = 6, n(T ∩ B) = 4, n(C ∩ T ∩ B) = 0

Now, n(C ∪ F ∪ V) = n(C) + n(T) + n(B) - n(C ∩ B) - n(T ∩ B) - n(C ∩ T) + n(C ∩ T ∩ B)

⇒ 84 = 28 + 40 + 48 - 6 - 4 -  n(C ∩ T)

⇒ n(C ∩ T)  = 116 - 10 - 84

⇒ n(C ∩ T) = 22

Hence, No. of Students who plays cricket but tennis = n(C) - n(C ∩ T)

                                                                                          = 28 - 22

                                                                                          = 6

Answered by rinarv0779
0

Answer:

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Step-by-step explanation:

u can u tell me the price of the day and i

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