Question

5. In a hotel, food is stored in a freezer at -20 °C
(1) What would be the temperature if it was raised by 5 °C?
(ii) What would be the temperature if it was lowered by 0.5 °C every hour for 12 hours?​

Answer 1

Answer:

1. -15°C
2. -26°C

Step-by-step explanation:

1. -20°+5° = -15°
2. 0.5(12) = 6

-20°-6° = -26°

Answer 2

$\boxed {\underline {\mathbb {PROPER\:QUESTION:-}}}$

In a hotel, food is stored in a freezer at -20 °C,

(1) What would be the temperature if it was raised by 5 °C?

(2) What would be the temperature if it was lowered by 0.5 °C every hour for 12 hours?​

$\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}$

(1) $\boxed{-15C}$

(2) $\boxed{-26C}$

$\boxed {\underline {\mathbb {GIVEN:-}}}$

food is stored in a freezer at -20 °C

(1) temperature if it was raised by 5 °C

(2) the temperature if it was lowered by 0.5 °C every hour for 12 hours

$\boxed {\underline {\mathbb {TO\:FIND:-}}}$

• What would be the temperature if it was raised by 5 °C?
• What would be the temperature if it was lowered by 0.5 °C every hour for 12 hours?​

$\boxed {\underline {\mathbb {SOLUTION:-}}}$

Food is stored at -20°C  

Situation of 1 part :-

It’s said that temperature is raised by 5°C $\implies {+5 \: C}$ [ ← increased i.e. we have taken as +5°C]

Temperature when raised $= -20+5$

$\boxed {\implies {-15 C}}$

Situation of 2 part:-

Current temperature $= -20$°C

Temperature lowered per hour $= -0.5$°C [← lowered i.e. we have taken as -5°C]

Hence temperature lowered in 12 hour $= -0.5 \times 12$  $=-6$°C

Temperature after 12 hours $= -20 -6$

$\boxed {\implies{-26C}}$

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