Question

5 In a quadrilateral ABCD, angle B = 90°. IF AD2 = ABP + BC2 + CD prove
angle ACD = 90°

Answer 1

Answer:

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Step-by-step explanation:

ABCD quadrilateral.  

angle ABC = 90 deg

hence,  AB² + BC² = AC²     --- (1)    using Pythagoras theorem.

AD² = ( AB² + BC² ) + CD²  given,

    =  AC² + CD²          ---- (2)

In the triangle ACD,  AD has to be a hypotenuse and angle ACD must be 90 deg. as per Pythagoras theorem.

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Answer 2

Step-by-step explanation:

ABCD quadrilateral angle ABC=90 degree. __1

hence AB2+B2=AC2

1)USING Pythgoras theorem

AD2=(AB2 +bc2 ) +CD 2 GIVEN

= AC2 +CD2 __________2

in the trangle ACD ,,AD HAS to be a hypotenuse

and angle ACD must be 90 degree as per phyagoras theorem

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