5. In a rhombus ABCD of side 6cm, find AC +BD
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Answer:
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Step-by-step explanation:
Please find below the solution to the asked query:
We follow these steps to construct rhombus ABCD by given information ( AB = BC = CD = DA = 6 cm and BD = 8 cm )
Step 1 : Draw a line BD = 8 cm
Step 2 : Now take radius of 6 cm and center B and D draw two arcs on both sides of line BD , These arcs intersect at " A " and " D " .
Step 3 : Join AB , AD , BC and DC . We get our required rhombus ABCD .
Now You can measure length of AC ( Other diagonal with the help of ruler ) by yourself .
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a rhombus ABCD of side 6cm, find AC +BD
Draw a diagonal AC=6 cm.
2. Draw a perpendicular bisector of AC, let the perpendicular bisector and AC intersects at O (∵ Diagonals of rhombus intersects at right angle)
3. Taking O as centre and half of the length of another diagonal (i.e 3.5 cm) as radius, mark arc on the perpendicular bisector at both sides of AC. Name these intersection points as B and D
4. Join AB,AD,BC,CD.
5. ABCD is the required rhombus.
6. Measure the length of any one side (∵ All sides of rhombus are equal), which come out to be 4.6 cm
Perimeter of rhombus =4× side =4×4.6=18.4 cm mark as