Question

5. In a rhombus of side 10 cm, one of the diagonals is 12 cm long. Find the length of the second diagonal​

Answer 1

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Side of rhombus :- 10 cm

Diagonal (1) = 12 cm

Let Diagonal (2) = x

Diagonal (2) = $\sqrt{4a²-D1²}$

=> $\sqrt{4(10)² - (12)²}$

=> $\sqrt{4 × 100 - 144}$

=> $\sqrt{400 - 144}$

=> $\sqrt{256}$

=> 16 cm

∴ Diagonal (2) = 16 cm