Question

5
In
a right triangle PQR , find angle Q if angle R is 46°​

Answer 1

Answer: Given,

ΔPQR is a right angled triangle

∠R= 46°

∠P= 90°

∠Q = x

Step-by-step explanation:

Sum of angles of triangle = 180°

Therefore ,

∠P+∠Q+∠R = 180°

90°+ x + 46° = 180 °

136° + x= 180°

x = 180° - 136°

x = 44°

Therefore , ∠Q = 44°

Answer 2

We know, Sum of all angles of a triangle is 180°

$\mathrm{\angle P + \angle Q + \angle R = 180°}$

$\mathrm{\therefore \: \angle \: Q = 180° - \angle \: P \: +\angle \:R }$

$\mathrm{ = \angle \: Q = 180° - 90° + 46°}$

$\mathrm{ = \angle Q = 180° - 136°}$

$\mathrm{\therefore \angle Q = 44°}$

$\boxed{\mathrm{\mapsto Verification}}$

$\mathrm{90° + 46° + 44° = \boxed{180°}}$