5. In a trapezium ABCD, AB || DC, AB = 30 cm, BC
= 15 cm, DC = 44 cm and AD = 13 cm. Find the
area of the trapezium.
Answers
Answered by
5
Area of trapezium = 444 cm²
Step-by-step explanation:
AB = 30 cm
CD = 44
Draw AM ⊥ CD & BN ⊥CD
AM = BN = y
MN = 30 cm
DM = x cm
=> CN = 44 - (30 + x) = 14 - x cm
AD = 13 cm
AD² = AM² + DM²
=> 13² = y² + x²
BC = 15 cm
=> BC² = BN² + CN²
=> 15² = y² + (14 - x)²
=> 15² - 13² = (14 - x)² - x²
=> 28 * 2 = (14) (1 4 - 2x)
=> 4 = 14 - 2x
=> 2x = 10
=> x = 5
13² = y² + x²
=> 13² = y² + 5²
=> y² = 144
=> y = 12
AM = BN = 12 cm
Area of Trapezium = (1/2) (AB + CD) * AM
= (1/2)(30 + 44) * 12
= 6 * 74
= 444 cm²
area of trapezium = 444 cm²
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