5. In a triangle ABC, prove that : cos
(A + B)/2=sin c/2
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Answer:
Step-by-step explanation:The sum of all angles in a triangle is 180°
Therefore,
A+B+C=180
A+B=180-C
(A+B)/2=(180-C)/2=90-C/2
cos(A+B)/2=cos(90-C/2)=sin C/2
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