Question

5.
In a vernier calliper, one main scale division is
x cm and n divisions of the vernier scale coincide
with (n-1) divisions of the main scale. The least
count (in cm) of the callipers is
nx
(1)
х
(2)
n
n-1
Х
(3)
Slx
(4)
n-1​

Answer 1

Answer :

n devisions of the vernier scale coincide with (n-1) divisions of the main scale.

One main scale division = x cm

We have to find least count of the vernier callipers in cm.

As given : n VSD = (n - 1) MSD

$\star$ VSD = Vernier scale division

$\star$ MSD = Main scale division

➝ n VSD = (n - 1) MSD

➝ 1 VSD = [(n - 1) / n] MSD

Least count of vernier callipers is given by

• LC = 1 MSD - 1 VSD

➝ LC = 1 MSD - [(n - 1) / n] MSD

➝ LC = [(n - n + 1) / n] MSD

➝ LC = 1/n MSD

ATQ, 1 MSD = x cm

➝ LC = x/n cm

Answer 2

Explanation:

LC=x/n cm

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