Question

5. In AABC, what value(s) of 'x' will make DE is parallel to AB, If AD=8x+9, CD=X+3, BE= 3X+4 and CE=X​

Answer 1

Answer:

x = -6/5 , 2

Step-by-step explanation:

By Basic Proportional Theorem-

CD/AD = CE/BE

x+3/8x+9 = x/3x+4

8x^2 + 9x = x ( 3x+4 ) + 3 (3x+4)

8x^2 +9x = 3x^2 + 4x + 9x + 12

8x^2 + 9x = 3x^2 + 13x + 12

5x^2 - 4x - 12 = 0

By Factorisation

5x^2 - 10x + 6x - 12

5x ( x-2) + 6(x-2)

(5x+6) ( x-2)

x=-6/5 & x=2. Answer.