5. In AABC, ZA = ZC. If exterior ZABX = 140°, find the angles of AABC.
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Answered by
0
Answer:
Where is Z in the figure.
Answered by
8
Answer:
LA = 70°
LABC = 40°
LC = 70°
Step-by-step explanation:
LA+LC = LXBA (Exterior angle property)
2LA = 140° (Since, LA=LC)
LA = 70°
LC = 70° (Since, LA=LC)
LXBA+LABC=180° (Linear pair)
140° + LABC = 180°
LABC = 40°
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