Question

5. In AABC, ZA = ZC. If exterior ZABX = 140°, find the angles of AABC.​

Answer 1

Answer:

Where is Z in the figure.

Answer 2

Answer:

LA = 70°

LABC = 40°

LC = 70°

Step-by-step explanation:

LA+LC = LXBA (Exterior angle property)

2LA = 140° (Since, LA=LC)

LA = 70°

LC = 70° (Since, LA=LC)

LXBA+LABC=180° (Linear pair)

140° + LABC = 180°

LABC = 40°

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