Question

5. In adjacent figure AC 1 CE and interior angles of AABC are in the ratio 2:2:1 respectively, then​

Answer 1

LET ANGLE 'A' BE '3X'

ANGLE 'B' BE 'X'

ANGLE 'C' BE 'X'

SO,

3X + 2X+ X=180

6X = 180

X = 30

SO,

ANGLE 'A' = 3X=3*30 = 90

ANGLE 'B' = 2X = 2* 30 = 60

ANGLE 'C' = X = 30

THAN,ANGLE ACE =ANGLE CAB + ANGLE ABC [SUM OF 2 INTERIOR ANGLE OF TRIANGLE IS EQUAL TO THE EXTERIOR ANGLE OF THIRD SIDE]

ANGLE ACE = 90+ 60

=150

THERE FOR,

ANGLE ECD = ANGLE ACE -- ANGLE ACD

150- 90

= 60

HOPE IT HELPS

MARK ME AS BRAINLIST

Answer 2

So, here is your answer.