Question

5. In an A.P. 17th term is 9 more than its 14th term. Find the common difference.​

Answer 1

Answer:

a17= 9+a14

a+16d= 9+a+13d

a-a= 9+13d-16d

-9= -3d

d= -9/-3

d= 3

Answer 2

Given : 17th term of AP is 9 more than its 14th term

To find : Common difference

Solution :

17th term of AP is 9 more than its 14th term

→ a17 = a14 + 9

→ a + 16 d = a + 13 d + 9

→ a + 16 d - a - 13 d = 9

→ 3 d = 9

→ d = 9/3

→ d = 3

So the common difference of AP is 3.