Math, asked by ravikumar952394, 8 months ago

5. In an annual examination, Ravi scored 81,67,78,92 and 88 marks in Science, English, Hindi, Mathematics,
and Social Science respectively. The maximum marks was 100. Determine the following.
(a) Aggregate percentage scored by Ravi
(b) If the topper scored 93% aggregate, then what percentage of the topper's aggregate did Ravi score?

Answers

Answered by tyrbylent
2

Answer:

Step-by-step explanation:

\frac{81+67+78+92+88}{5} = 81.2

(a). 81.2 %

(b). 93% - 81.2 % = - 11.8 %

Answered by royrahulan1998
1

Answer:

Total marks= 81+67+78+92+88=406

Maximum marks in total = 5*100=500

Aggregate percentage scored by Ravi=(406/500) *100=81.2%

Topper's total marks =(93/100) *500=465

Percentage of the topper's aggregate did Ravi score=(406/465) *100=87.31%

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