Question

5) In an AP the T6 = 19 and the T11 = 34
Find:- a) the first term b) The common difference
c) The S20 term

Answer 1

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Answer 2

T6=a+5d=19

T11=a+10d=34

d=3

a+5d=19

a=4

s20=n/2(2a+19d)

=20/2(2*4+19*3)

=10(8+57)

=65*10

650

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