5. In an auditorium, 300 tickets were sold. The total sale of tickets was 1250. If the tickets were of two denominations of 2.50 and 5.00. How many of each denomination were sold.
Answers
Step-by-step explanation:
1)In an auditorium, 300 tickets were sold. The total sale of tickets was 1250. If the tickets were of two denominations of 2.50 and 5.00. How many of each denomination were sold.
Solution:
Let the number of tickets of Rs 2.50 be x and the number of tickets of Rs 5 be y.
Total number of tickets = (x + y).
(x + y) = 300-------------------------(1)
Total amount from the sale of the tickets
=> Rs 1250.
=>(2.50x + 5y) = 1250---------------(2)
By solving equations (1) and (2), we get x = 100 and y = 200.
Therefore, number of tickets of denomination Rs 2.50 is 100 and the number of tickets of denomination Rs 5 is 200.
Explanation: PLS MARK ME AS BRAINLIEST AND (FOLLOW)-(ME):
Answer:
let 'a' is the of rupees of rs.2.50 tickets and 'b' the number of rs.5 ticket
a+b =300...(1)
2.5a + 5b = 1250...(b)
EQ (1) ×5 =1500
5a + 5b = 1500
2.5a+5b =1250
_____________
2.5a =25a
25a =250
a = 100
a+b = 300
100 + b = 300
b = 200
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. .These are the 100 RS2.50 tickets and 200 RS5 ticket