Question

5. In each of the following figures, find x and y when AB II CD
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Answer 1

ANSWER IS IN THE PHOTO

PLEASE SEE THE PHOTO FOR ANSWER

Answer 2

Step-by-step explanation:

In the first one

we know that Ina triangle sum of all interior angles is 180°

so if we take angle ACB as x''

then a= 180-(64+72)

= 180-136

I.e a=44°

now, AB is parallel to CD (given)

so angle ABC = angle CDE=72°

I.e Angle CDE (or angle 'y')=72°

Now if we consider the straight line BCE (I.e is the angle is 180°)

44°+x+72°= 180°

I.e x= 180- (44+72)°

= 180-116

=64°

so we can say that x= 64° and y= 72°

qn 2)

sum of all interior angles of a triangle is 180° therefore

angle ACB is 180-(57+63)= 60°

given AB is parallel to CD

then angle CBA = angle DCB

I.e angle DCB ( or y ) = 63°

now considering straight line ACE

then angle

ACB +angle BCD + angle ECD= 180°

therefore

60+63+x = 180°

x= 180-(60+63)

x= 180-123°

I. e x = 57°

y= 63°

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Hope it helps you;)