Question

5. In Fig. 15.197, A is the centre of the circle. ABCD is a parallelogram and CDE is a
straight line. Find angle BCD: angle ABE.
25
Fig. 15.197​

Answer 1

angle BCD is 90 degree as CD is a tangent to the circle and its angle will 90 degree therefore angle CDA is 90 degree and angle CDA is a angle of parallelorgam then angle ABCwill also be 90 degree and angle BCD will also be 90 degree