Question

5. In Fig. 2, PQ I BA and PR I BC, such that PQ = PR.
Show that BP bisects ZABC.​

Answer 1

Answer:

We have,

∠1=∠2 [∵ BP is the bisector of ∠ABC]

∠1=∠3 [∵PQ∥BA]

∴∠2=∠3

⇒PQ=BQ

⇒ΔPBQ is isosceles.

solution