5. In Fig. 6.20, DE || OQ and DF l| OR. Show that
EFIlQR
Answers
Answered by
41
Given : DE || OQ and DF || OR.
To prove EF || QR.
Since DE || OQ so we have
.........................1
Also, DF || OR
.........................2
From equation 1 and 2, we have
Thus, EF || QR. (converse of basic proportionality theorem)
Hence proved
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Answered by
2
Answer:
HELLO MATE ,
EF//QR [CONVERSE OF BPT]
Step-by-step explanation:
GIVEN;
DE//OQ
DF//OR
PROVE;
EF//QR
SOLUTION;
IN ΔPOQ , DE//OQ
IN ΔPOR , DF//OR
From equation 1 and 2
IN ΔPQR , EF//QR
THEREFORE, EF//QR [converse of BPT]
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