Question

5. In Fig 7.28, ray AZ bisects ∠DAB as well as

∠DCB.

(i) State the three pairs of equal parts in

triangles BAC and DAC.

(ii) Is ∆BAC ≅ ∆DAC? Give reasons.

(iii) Is AB = AD? Justify your answer.

(iv) Is CD = CB? Give reasons.​

Answer 1

Answer:

In BAC and DAC, the three pairs of equal parts are as given below:

DAC = CAB (AZ bisects BAD)

DCA = ACB (AZ bisects BCD)

and AC = AC (Common in both)

(ii) From (i) above, BAC DAC (By ASA congruence rule)

(iii) AB = AD (Corresponding parts of congruent triangles)

(iv) CD = CB (Corresponding parts of congruent triangles)

Step-by-step explanation:

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