Question

5. In Fig. 7.49, angle B< angleA and angleC< angleD. Show that
AD <BC.​

Answer 1

Answer:

Let the point of intersection of BC and AD be O

In △ABO  

⇒∠B<∠A

Thereore, ⇒AO<BO     (1)                   (side opposite to greater angle is largest)

Similarly,  

In △COD  

⇒∠C<∠D

Thereore, ⇒DO<CO        (2)             (side opposite to greater angle is largest)

Adding (1) and (2) we get,

⇒BO+OC>AO+DO

⇒BC>AD

Hence proved.

Step-by-step explanation: