5. In Fig. 8.13, find tan P-cot R.
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Answer:
In △PQR
PR
2
=PQ
2
+QR
2
....(Pythagoras theorem)
13
2
=12
2
+QR
2
QR
2
=
169−144
=
25
=5 cm
tanP=
PQ
QR
=
12
5
,cotR=
PQ
QR
=
12
5
∴tanP−cotR=
12
5
−
12
5
=0
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