Question

5. In Fig. 9.44, ABC is an isosceles triangle in which AB = AC. Also, D is a point such that
BD = CD. Prove that AD bisects A and D.​

Answer 1

Step-by-step explanation:

In ∆ABD and ∆ACD,

AB= AC (given)

BD = CD ,(given)

AD =AD (common)

hence, ∆ABD ~ ∆ACD (by SAS rule)

<BAD = <CAD and <BDA = <CDA (by cpct rule)

AD bisects A and D...

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