Question

5. In figure 1.74, PM = 10 cm
A(APQS) = 100 sq.cm
A(AQRS) = 110 sq.cm
then find NR.​

Answer 1

Answer:

11

Step-by-step explanation:

area of PQS = 100

area of PQS = (1/2)*base*height= (1/2)*(QS) *(PM)

100= (1/2)*(QS) *10

QS= 2*100/10= 20

so area of QRS = (1/2)* QS*NR

110= (1/2)*20*NR

NR= 220/20

NR= 11