Question

5. In figure EF || DQ and AB || CD. Find ZPDQ, ZAED and ZDEF.
P
F
27
D
64°
A
E
B​

Answer 1

Answer:

Ang PDQ = 89 °

Ang. AED = 27°

Ang. DEF = 89°

Step-by-step explanation:

Ang. PDC =27° = Ang. AED = 27° (corresponding angles) as CD||AE AND PE is transversal..

Ang. DEF = 180-(27+64) (by linear pair property)

Ang. PDQ =Ang. DEF =89° (Corresponding angles)... As EF||DQ AND PE is transversal...

HOPE THIS WILL HELP YOU!!!