5. In first case, a force of 5 N is applied on a object for
6 minutes and displaces it by 10 meters. In second
case, A force of 10 N is applied on the same object for
3 minutes and displaces it by 5 meters. In which case
there is more work done?
A) First case
B) Second case
C) In both cases, work done is same
D) In both cases, work done is zero
Answers
Answered by
0
Answer:
i. work done = 5*10=50J
ii.w = 50J
Explanation:
Answered by
0
Answer:
(c)
Explanation:
Work done = Force x Displacement in the direction of force
case 1 W = 5 x 10 = 50 J
case 2 W = 10 x 5 = 50 J
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