Question

5
in the above diagram. The work during a cycle
is
1) 2PV
B
(3P, 3V)
S
2) PV
1
3
2PV
A
(P.VE
1
C С
(P.3V)
E
D
4) Zero
44. An Ideal gas is taken around ABCA as shown​

Answer 1

Answer:

The work done during a cycle is equal to the area under a P−V diagram.

From the given P−V diagram.

W=

2

1

×AC×BC

W=

2

1

×(3V−V)×(3p−p)

W=

2

1

×2V×2p

W=2pV

The correct answer is 2p V