Question

5. In the adjoining figure, ABCD is a quadrilateral in
which AD = BC and angle DAB = angle CBA. Prove thaT
(1) TIRANGLE ABD = TRIANGLE BAC
(ii) BD = AC
(iii) ANGLE ABD = ANGLE BAC.​

Answer 1

angel abd=angle bac. ........................

Answer 2

Answer:

in triangle ABD and triangle BAC

AB=BC (GIVEN)

∠DAB = ∠ CBA (GIVEN)

AB = BA (COMMON)

THEREFORE, TRIANGLE ABD ≅ TRIANGLE BAC ( BY SAS)

THEREFORE, BD = AC (CPCT)

ALSO, ∠ ABD = BAC (CPCT)