Question

5. In the adjoining figure, BM I AC and
DN 1 AC. If BM = DN, prove that AC
bisects BD.​

Answer 1

Answer:

It is given that BM ⊥ AC and DN ⊥ AC

From the figure we know that ∠ DON and ∠ MOB are vertically opposite angles

∠ DON = ∠ MOB

Since DN and MB are perpendiculars

We know that

∠ DNO = ∠ BMO = 90o

It is given that BM = DN

By AAS congruence criterion

△ DNO ≅ △ BMO

OD = OB (c. p. c. t)

Therefore, it is proved that AC bisects BD.

Step-by-step explanation:

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