Question

5. In the adjoining figureZ ADC = 80°, then
L CBE = ?
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Answer 1

$\huge \underbrace \mathfrak \red{Explanation }$

$\angle ADC + \angle CBE =180°$[opp. side of cyclic quadrilater]

$80° + \angle CBE=180°$

$80° + \angle CBE = 180°$

$\angle CBE = 180° -80°$

$\blue{\angle CBE = 100°\: Ans}$