Math, asked by SRAVANA1917, 4 months ago

5. In the expansion of (x+xlog10%)5, the third term is 10⁶, then x=
1) 1
2) 2
3) 10
4)100
answer this question correctly who answered first I will follow them​

Answers

Answered by gumnaambadshah
2

Answer:

A helicopter is ascending with a velocity of 2 m/s at a height of 24 m when it drops a mail packet. The packet contains material, which can be damaged if it hits ground with velocity of magnitude greater than 72 km / h. Was the packet damaged? Explain your answer.

(Take g = 10 m/s2)

Ans

As the packet reaches the ground with a velocity (22 m/s) greate

Ans

As the packet reaches the ground with a velocity (22 m/s) greater than the safe velocity of 20 m/s, so it is damaged.

A helicopter is ascending with a velocity of 2 m/s at a height of 24 m when it drops a mail packet. The packet contains material, which can be damaged if it hits ground with velocity of magnitude greater than 72 km / h. Was the packet damaged? Explain your answer.

(Take g = 10 m/s2)

Ans

As the packet reaches the ground with a velocity (22 m/s) greate

Ans

As the packet reaches the ground with a velocity (22 m/s) greater than the safe velocity of 20 m/s, so it is damaged.A helicopter is ascending with a velocity of 2 m/s at a height of 24 m when it drops a mail packet. The packet contains material, which can be damaged if it hits ground with velocity of magnitude greater than 72 km / h. Was the packet damaged? Explain your answer.

(Take g = 10 m/s2)

Ans

As the packet reaches the ground with a velocity (22 m/s) greate

Ans

As the packet reaches the ground with a velocity (22 m/s) greater than the safe velocity of 20 m/s, so it is damaged.

Answered by shresthtrivedi123
1

Answer:

ANSWER

Given T

3

=10

6

5

C

2

x

3

(x

log

10

x

)

2

=10

6

⇒10x

3

(x

2log

10

x

)=10

6

⇒x

3

(x

2log

10

x

)=10

5

Taking log with base 10 on both sides,

log

10

x

3

+log

10

(x

2log

10

x

)=5

⇒3log

10

x+2(log

10

x)

2

−5=0

Put log

10

x=t

⇒2t

2

+3t−5=0

⇒t=1,−

2

5

⇒x=10

1

;x=(10)

−5/2

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