5. In the figure, ABCD is a parallelogram and E is the midpoint of side BC. If D
DE and AB when produced meet at F. Prove that AF = 2AB.
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Solution :-
in the figure
△DCE and BFE
any DEC = any BEF (vertically opp any)
EC=BE (E is the mid point)
∠DCB=∠EBF (alternate angle DC parallel to AF)
So △DCE congruent to △BFE
Therefore DC=BF ...(1)
now CD = AB (ABCD is a parallelogram)
soAF=AB+BF
=AB+DC from (1)
=AB+AB
=2AB
Answered by
1
Answer:
2Ab
Step-by-step explanation:
Solution :-
in the figure
△DCE and BFE
any DEC = any BEF (vertically opp any)
EC=BE (E is the mid point)
∠DCB=∠EBF (alternate angle DC parallel to AF)
So △DCE congruent to △BFE
Therefore DC=BF ...(1)
now CD = AB (ABCD is a parallelogram)
soAF=AB+BF
=AB+DC from (1)
=AB+AB
=2AB
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