Question

5. In the figure, ABCE and ABDE are cyclic quadrilaterals. Given that ​

Answer 1

Answer:

Given, ∠EAB=120

o

,∠EPD=100

o

,∠EDB=60

o

(ABCD is a cyclic quadrilteral, opposite angles are supplementary, 180−120=60

o

)

∠ECB=60

o

- (Same arc angle equal)

In ABPC,∠C=60,∠P=100

o

∠B=180−(100+60)=20

o

ie., ∠DBC=20

o

Explanation

This answer is right