Question

5) In the figure, O is the centre of a circle, AC is a diameter. If ACB = 50°, then find the measure of BAC.
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Answer 1

Answer:

40⁰

Step-by-step explanation:

because angle CBA is 90⁰ so that angle BAC is 180⁰-(90⁰+50⁰)= 40⁰

Answer 2

From the given figure , two triangles are formed ,

i.e. Triangle BCO and Triangle BAO,

From the given figure ,

OC = OA { Radius }

OB = OB

Angle BOC = Angle BOA = 90° {OB is perpendicular to the given diameter}

Hence , Triangle BCO and BAO are congruent

Therefore, Angle BAO is 50°