Question

5. In the figure, OA = OB and OD=OC. Show that ∆AOD = ∆BOC.
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Answer 1

$\large\sf{(i)OA=OB(given)}$

$\large\sf{OD=OC(given)}$

$\large\sf{\angle{AOD}and\angle{BOC}(V.O.A)}$

$\large\sf{\angle{AOD}=\angle{BOC}}$

$\large\sf{∆AOD\:\cong\:∆BOC}$

$\large\sf{By\:SAS\:congruence\:rule}$

$\large\sf{(ii)\angle{OAD}=\angle{OBC}(pair\:of\:alternate\:angles\:of\:AD\:and\:BC)}$

$\therefore$$\large\sf{AD||BC}$