5. In the figure P | Q and r is a transversal. If <1 and<2 are in the ratio 3:2 determine the angles from <1 to<5?
Answers
Answered by
798
Given:-
- In the figure P | Q and r is a transversal
- <1 and<2 are in the ratio 3:2
To find :-
- Determine the angles from <1 to<5?
Solution:-
Now,
ㅤ ___________________
ㅤ
ㅤㅤㅤDEFINITIONS
ㅤ
Alternate Interior Angles:
These angles are formed when two || and non || are intersected by any transversal.
Vertically Opposite Angles:
These angles are vertically Opposite from each other at any vertex as in attached figure
Linear Pair Angles:
When two lines Intersect each other at any single point then two pair of angles are called linear pair.
Answered by
7
Answer:
Given:-
In the figure P | Q and r is a transversal
<1 and<2 are in the ratio 3:2
To find :-
Determine the angles from <1 to<5?
Solution:-
\sf\angle1 : \angle2 = 3:2∠1:∠2=3:2
\sf\angle 1 = 3x\:and \angle 2 = 2x∠1=3xand∠2=2x
\sf Line\:t\:stands\:on\:the\:line\:PLinetstandsonthelineP
\sf{\implies \angle 1 + \angle 2 = 180°\:\:\:(linear\:pair)}⟹∠1+∠2=180°(linearpair)
\sf{\implies 3x + 2x = 180}⟹3x+2x=180
\sf{\implies 5x =180°}⟹5x=180°
\sf{\implies x =\dfrac{180°}{5}}⟹x=
5
180°
\sf{\implies x =36}⟹x=36
\sf Therefore,\: \angle 1 = 3x = 108°Therefore,∠1=3x=108°
Now,
\sf \angle\:1 = \angle 5 =\:108\:\:(Pair\:of\:corresponding\:angles)∠1=∠5=108(Pairofcorrespondingangles)
ㅤ ___________________
ㅤ
ㅤㅤㅤDEFINITIONS
ㅤ
Alternate Interior Angles:
These angles are formed when two || and non || are intersected by any transversal.
Vertically Opposite Angles:
These angles are vertically Opposite from each other at any vertex as in attached figure
Linear Pair Angles:
When two lines Intersect each other at any single point then two pair of angles are called linear pair.
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