Question

5. In the figure shown below, AD || BD AD = 12 cm and BC = 18 cm. Also, diameter of the semicircular part, CD = 8 cm. Find the area and the perimeter of the figure.
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Answer 1

Answer:

Solution

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Since, Length of AB, BC and CD are equal.

Radius of circle =6cm

Now, AD=2×6=12cm

⇒AB+BC+CD=12

⇒3AB=12

⇒AB=

3

12

⇒AB=4cm

⇒AB=BC=CD=4cm

Radius of semicircle AB=2cm

Radius of semicircle BC=4cm

Radius of semicircle AD=6cm

Area of the shaded region = Area of semicircle (AB+AD) − Area of semicircle (BD)

⇒ Area of shaded region =0.5π(2

2

+6

2

)−0.5π(4)

2

⇒ Area of shaded region =0.6π(4+36)−0.5π×16

⇒ Area of shaded region =20π−8π

⇒ Area of shaded region =12πcm

2

.

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