Question

5. In the given figure, ABCD is a parallelogram.
Prove that : AB = 2 BC.

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Answer 1

Answer:

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Answer 2

Answer:

Given -

ABCD is a parallelogram

To Prove -

AB = 2 BC

Proof -

ABCD is a parallelogram

A + D + B + C = 180°

From the aeb we have,

$= > \: \frac{a}{2} + \frac{b}{2} + e = 180$

$= > \: a - \frac{a}{2} + d + e = 180$

$= > \: a + d + e = 180 + \frac{a}{2}$

$= > \: e = \frac{a}{2}$

Again,

$e = \frac{b}{2}$

Now,

$ab = de + ec$

$= > \: ad + bc$

$= > \: 2bc \: \: \: \: \: \: \: (since \: ad = bc)$

Hence proved

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