Question

5. In the given figure, O is the centre
of a circle, BC is its chord and A
is
any point on the circle. If ZBAC
= a and ZOBC = b, find a + b.

Answer 1

Answer:

Step-by-step explanation:

∠O= 2∠A

in ΔOBC

OB = OC

∠B=∠C

∠B+∠C+2∠A = 180°

2∠B+2∠A=180°

∠A+∠B= 90°

Answer 2

Answer:

$\fbox\blue{your\:ans = 90°}$

in circle ob = oc = radius

∆o = 2∆A = 29°

angle at centre is twice of angle at circumference sum of angle of angle OBC

∆ OPC + ∆ ocb + 29 = 180°

29 + 2b = 180°

a + b = 90°