Question

5. In the given figure, side BC of a triangle ABC
has been produced to D and CE II BA. If
ZABC = 65°, ZACE = 55°, find ZBAC, ZACB
and ZECD.
A
E
55°
65°
B
C
D​

Answer 1

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Step-by-step explanation:

hence, we know the sum of the angles of triangle is 180 degree

so , so we must subtract angle ABC + angle BAC ( 65 + 55 ) that is 120 from 180 that is,

(180 - 120) = 60 that is ACB = 60

the angle ACD = 120

because (180 - 60) = 120

and ECD as vertically opposite to BCA

It's also 60 degree

and ACE = 180 - (ACB + ECD)

that is 180 - (60 + 60)

180 - 120

= 60

so ACE = 60 , ECD= 60 , ACB = 60