Question

5. In the given figure, the lengths of arcs ad
and BC are in the ratio 3 : 2.
If AOB = 96°, find:
(i) angelBOC
(ii) angelABC​

Answer 1

Answer:

Step-by-step explanation:

OAB and OBC are isosceles triangle

Let angle oab=abo=x

Let angle obc=bco=y

2x+96=180

x=42

ab/bc=3/2

2ab=3bc

2x96*2πr/360=3xα*2πr/360

(where α=angle boc)

2*96=α*3

α=64

in triangle boc,

2y+64=180

y=58

x+y=42+58=110

And hence,

angle boc=64

angle abc=110

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