Question

5. In the given pair of linear equations x + 2y = 4 and 4x – 2y = 6. Find the
value of x.
2 x 8 = 16
uitable method.​

Answer 1

Answer:

value of x= 1

Step-by-step explanation:

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Answer 2

Answer:

x+ 2y=4 , 4x-2y=6

by substitution method-

x=4-2y........(1)

x=6+2y/4. ......(2)

putting the value of X from eqn 1 to 2, we get

4-2y=6+2y/4

-2y/1-2/4y=6-4

LCM of 4 and 1 in LHS

(-8y-2y)/4=2

-10y/4=2

-10y=2*4

-y=8/10

y=-4/5

now, from eqn 1

x=4-2y

x=4-5*4/5

x=4-1*4/1

x=3*4

x=12

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