Question

5. In the reaction represented by the equation 2NaCl + H2SO4=Na2 SO4 + 2HCl. Calculate the volume of
hydrogen chloride that can be obtained at s. t.p from5.85g of sodium chloride (H = 1, Na = 23, Cl =35.5,molar​

Answer 1

Answer:

2.24 litre

Explanation:

from the above equation we can see that

From 2 moles of NaCl we get 2 moles of HCl

so number of moles of NaCl and HCl should be same

Number of moles of NaCl =

Given weight ÷ Molecular Mass -->

5.85 ÷ 58.5 = 0.1

0.1 is the number of moles of NaCl

0.1 will also be the number of moles of HCl according to the equation.

Here we have to find the volume of HCl we get

and we know volume at STP of gas is 22.4 L

so

Number of moles = volume ÷ 22.4

after putting values,

we will get

volume of HCl obtained = 2.24 L

Hope this answers the question