Math, asked by parthkanwar28, 10 months ago

5. In triangle ABC, right-angled at B if sin A = 1/2, find the value of
1. sin C cos A – cos C sin A
2. cos A cos C + sin A sin C

Answers

Answered by velampati2001
40

Step-by-step explanation:

given sin A =1/2 A is 30 degrees

angle B is 90 degrees

then value of angle C is 180-(90+30)=60 degrees

sin C is sin 60 is √3/2

cos C is cos 60 1/2

sin A is sin 30 =1/2

cos A is cos 30=√3/2

sinC.cosA-cosC.sinA=√3/2*√3/2-1/2*1/2

=3/4-1/4=1/2

cos A.cosC+ sinA.sinC=√3/2*1/2+1/2*√3/2

=√3/4+√3/4=2√3/4=√3/2

I hope it helps you

Answered by sejaldhoke74
30

Step-by-step explanation:

I hope this is helpful for you .

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