5 indistinguishable balls are placed in 6 cells find probability of 1st and 3rd cells are empty
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Answer:
Let a and d be the first term and common difference for an AP.
number of terms of AP = n
last term = nth term = l
Given:
a = 17
d = 9 ,
l = 350
a + ( n - 1 ) d=nth term
=> 35017 + ( n - 1 ) 9 = 350
=>( n - 1 ) 9 = 350 - 17
=>( n - 1 ) 9 = 333
=>n - 1 = 333 /9
=>n - 1 = 37
=>n = 37 + 1
=>n = 38
Therefore ,
Number of terms in given AP =
\pink{\bold{n=38}}n=38
━━━━━━━━━━━━━━━━
The terms are:-
\red{17, 26, 35....350}17,26,35....350
━━━━━━━━━━━━━━━━
Additional:
How to find the sum of the terms of AP?
let Sum of n terms of AP = Sn
We know,
Sn = n /2 ( a + l )
Here n= 38 (as we calculated)
putting values we get:
Sum = 38 / 2 [ 17 + 350 ]
= 19 × 367
= 6973
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