Question

5 into 10 to the power 15 electrons are flowing per second through the cross section of the conductor find the strength of the current through the conductor​

Answer 1

Answer:8*10^(-4) A

Explanation: no. of electrons=5*10^(15)

Time taken(t) = 1 sec

We know that,

6.25*10^(18) electrons=1C

5*10^(15) electrons= 5*10^(15) /6.25*10^(18)

1/1250 C =5*10^(15) electrons

1/1250 C = Q (quantity of charge)

We know that,

I=Q/t

I=1/1250*1

I=1/1250

I= 0.0008 A

I=8*10^(-4) A