Question

5 is one of zeroes of the polynomial P(x]=_223-5x²
-3x+30.
to​

Answer 1

Answer:

hy

Step-by-step explanation:

Given polynomial is p(x) = 2x3-5x2+px+b

Since x = 2 is zero of the given polynomial, we have p(2) = 0

Now put x = 2 in p(x)

p(2) = 2(2)3 – 5(2)2 + p(2) + b

⇒ 0 = 16 – 20 + 2p + b  

⇒ 2p + b = 4 → (1)

It is also given that x = 0 is also a zero of the given polynomial

Hence p(0) = 0

Put x = 0 in p(x), we get

p(0) =  2(0)3 – 5(0)2 + p(0) + b

⇒ 0 = 0 – 0 + 0 + b  

∴ b = 0

Put b = 0 in (1), we get

2p + 0 = 4

∴ p = 2