5. It is found that the resistance of a coil of wire increases from 50 Ω at 15 0
C to 58 Ω at 55 0
C. Calculate
the temperature co-efficient of resistance of the material.
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Answer:
Temperature coefficient = 4 × 10⁻⁴ C⁻¹
Given:
Initial resistance = 50 Ω
Final resistiance = 58 Ω
Initial temperature = 150° C
Final temperature = 550° C
To Find:
Temperature coefficient of resistance of the material
Solution:
The temperature coefficient of a material is given by the equation,
where R is the final resistance, R₀ is the initial resistance, α is the temperature coefficient of the material, T is the final temperature, T₀ is the initial temperature.
Substitute the given data,
Therefore the temperature coefficient of the material is 4 × 10⁻⁴ C⁻¹
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