Question

5 kg gun fires a bullet of 15 grams at a velocity of 1000 metre per second to the right what is the velocity of the recall of the gun please give me a step-by-step solution I have aked many times but nobody is given a step-by-step solution if anybody will give me step-by-step solution I will mark in brainly plzz answer I will mark them brainliest

Answer 1

GIVEN:-

Before Firing gun was at rest.

• $\tt{Mass\:of\:gun(m_1)= 5kg}$

• $\tt{Mass\:of\:bullet(m_2) = 15g = 0.015kg}$

• $\tt{Initial\:Velocity\:of\:gun\:and\:bullet = u_1 = u_2 = 0m/s}$.

After Firing

• $\tt{Mass\:of\:bullet(m_1)= 0.015kg}$

• $\tt{Mass\:of\:gun(m_2) = 5kg}$

• $\tt{Final\:Velocity\:of\:Bullet(v_1) = 1000m/s}$

• $\tt{Recoil\:Velocity\:of\:the\:gun = v_2 = ?}$

According the Conservation of momentum,

Total Momenta before Collision = after Collision.

So,

$\implies\tt{ m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2}$

$\implies\tt{ 5(0) + 0.015(0) = (0.015)(1000) + (5)(v_2)}$

$\implies\tt{ 0 = 15 + 5v_2}$

$\implies\tt{ -15 = 5v_2}$

$\implies\tt{ v_2 = \dfrac{-15}{5}}$

$\implies\tt{ v_2 = -3m/s^{-1}}$.

Hence, The recoil Velocity of Gun is -3m/s